Therefore, the minimum scanning speed should be one that provides viewing at least two or, for greater reliability, three binary inputs coming from the car of the minimum length moving at maximum speed, the length of the car instead of the width of the detector loop to take equal to 20 foot (6096 mm) , and the speed of the car is 90 miles (144 kmh), then the minimum viewing speed should be approximately 20 views.
Such a viewing speed allows you to reliably determine the interval between cars up to 150 msek, which at a speed of 10 miles (16 km h) corresponds to a distance of approximately 2 foot (610 mm).
If one detector serves two lanes, the position changes, since the possibility of crossing it by cars with a different relative location is created, starting from simultaneously crossing two cars, which are exactly side by side, and ending with their complete separation. If we assume that the distances between cars in each lane are distributed equally and the minimum interval between cars in each lane is 1.8 seconds, then the minimum probable time interval, which should be perceived, will be approximately 18 msek, which requires viewing the viewing speed of about 100 seconds.
If we accept that the amount of the length of the car and the width of the detector loop is 20 foot (6096 mm), and the minimum viewing speed of 20 seconds, then this error can be approximately 0.25%, which is not significant, given the other inaccuracies inherent in the detector process.
If the input scanning device works in the described manner, then the number of bits (double signs), which should be stored in the memorable device of the computing machine 418 during the period of capture of any given duration, directly in proportion to the viewing speed.
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